A manual of exercises in forest mensuration

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1915 Excerpt: ...case the defect per lUjeal foot should be multiplied by the total length'of the defect ajd the result subtracted from tSe full scale. 3 Example: If a log has a pitch ring 20inches in diameter and a wasJte thickness: of 4 inches, the defect to board feet per lineal foot will be Jfound in the column headed "4" under "Pitch Rings" opposite 20 in the "Diam." column, whichMn this case is 21 board feet. Multiply this defect per lineal foot b$t the distance the pitch ring extends into log and the result will e the total number of feet B. M. defect caused by the ring. Example: If a log has a pitch seam 16 inches in width across the end of the log and a waste thickness of 2 inches tHe defect in board feet per lineal foot will be indicated in the column headed "2" under "Pitch Seam" opposite 16 in the "Diam." column, which in this case is 2.6 board feet. Multiply this defect per lineal foot by the distance the seam extends into the log, and the result will be the total number of feet B. M. defect caused by the seam. Example: If a log has a uniform rot 15 inches in diameter, the defect in board feet per lineal foot will be indicated in the column headed "Rot" opposite 15 in the "Diam." column, which in this case is 17 board feet. Multiply this defect per lineal foot by the distance the rot extends into the log and the result will be the total number of feet B. M. defect caused by the rot. In using the pitch ring table it will be noted that for a waste thickness of 8 inches the defect per lineal foot amounts to % the diameter (D.) for diameters up to 18 inches, and to % D plus 1 for diameters 18 inches and above; for a waste thickness of 4 inches the defect per lineal foot amount to D. for ...