Computer code for predicting coolant flow and heat transfer in turbomachinery
Book Details
Author(s)U.S. Government
PublisherBooks LLC, Reference Series
ISBN / ASIN1234335948
ISBN-139781234335946
AvailabilityUsually ships in 24 hours
MarketplaceUnited States 🇺🇸
Description
Original publisher: Washington, D.C. : National Aeronautics and Space Administration, Office of Management, Scientific and Technical Information Division ; [Springfield, Va. : For sale by the National Technical Information Service], 1990. OCLC Number: (OCoLC)34352284 Subject: Turbomachines -- Cooling -- Computer simulation. Excerpt: ... EXAMPLE PROBLEM 2 ( CALCULATION ACCURACY ) EXAMPLE PROBLEM 3 ( FANNO AND RAYLEIGM LINE ) RDATT IECHO = O, IUNITS:I, IOPPRP = O, RG: 287.053, RPM:O.O, & DATT IECHO = O, IUNITS:I, IOPPRP = O, RG: 287.053, RPM = O.O, G:I. 39, CP = 0.2G, XMU: 2.65E-4, XK = O.g5E-Q, 0: i. 40, CP = 0.23978, XMU:I, 8E-Q, XK = O. 6E-4, NI = I, ZIN = D.O, RIN:O.O, YIII = O.O, AIN = IO.D, DHIN = I.O, 14I = i, ZIN = O.O, RIN = O.O, YIti:O.O, AIN = IO.O, DHIN = 3.56825, PTSP = IO0., TTSP = 500., KTIN = O. 0, POUT = 65. D, IOPTN = O, HIN =. 787355, Z = IO.O, R = O + D, Y = O.O, A = 5.0, IOPTH = O, NIN = O.B721, PTSP = IO0. O, TTSP = 300. O, KTIN = O.O, Z: 128.50803, R = O.O, Y = O.O, NSLI = 50, A:IO.O, HC = O.O, DH: 3.56825, IOPTFI = O, IOPTHT = O, IOPTFF = O, NSLI = 2, F:O.IO, TN: 500. & END HC = O.O ) DH = I. 0, F = O.O, TN = IOOD. & END RDATT NSLI = IO0 RERD & DATT NSLI = 5 & END 8DATT NSLI = I50 REND & DATT NSLI = IO & END & DATT Z: 12.576, F = O.O, HC = 2.0, TN: 2000., NSLI = 50 REND & DATT NSLI: 20 & END gDATT Z: 12.574, NSLI:IOO REND " RDATT NSLI = _O & END & DAFT Z: 12.572, RSLI = 150 8END & DATT NSLI = 60 & END & DATT NSLI = 80 & END Figure l l.--Examplc 3 input data. & DATT NSLI = IO0 & END & DATT NSLI = I25 & END & DATT NSLI = I50 & ENDUT = 96. D, & DATT AIN = 5.0, PO A = IO.O, MIN = O. 88_3, NSLI = 2 & END RDATT NSLI = 5 & END 8DATT NSLI = IO & END RDATT NSLI = 2O & END RDATT NSLI = qO REND RDATT NSLI = 60 REND TABL [: " 111, SUMMARY OF EXAMPI + E 3 RESUI + TS & DATT NSLI = 80 & END & DATT NSLI = IO0 & END gDATT NSLI = 125 ...










